JEE Mains · Chemistry · STD 11 - 9. Hydricarbon
Benzene on nitration gives nitrobenzene in presence of \(\mathrm{HNO}_{3}\) and \(\mathrm{H}_{2} \mathrm{SO}_{4}\) mixture, where :
- A \(\mathrm{HNO}_{3}\) acts as an acid and \(\mathrm{H}_{2} \mathrm{SO}_{4}\) acts as a base
- B both \(\mathrm{H}_{2} \mathrm{SO}_{4}\) and \(\mathrm{HNO}_{3}\) act as a bases
- C \(\mathrm{HNO}_{3}\) acts as a base and \(\mathrm{H}_{2} \mathrm{SO}_{4}\) acts as an acid
- D both \(\mathrm{H}_{2} \mathrm{SO}_{4}\) and \(\mathrm{HNO}_{3}\) act as an acids
Answer & Solution
Correct Answer
(C) \(\mathrm{HNO}_{3}\) acts as a base and \(\mathrm{H}_{2} \mathrm{SO}_{4}\) acts as an acid
Step-by-step Solution
Detailed explanation
Reagent for nitration of Benzene \(\underset{(\text { Acid })}{{H}_{2} \mathrm{SO}_{4}}+\underset{(\text { Base })} {HNO} \rightleftarrows {HSO}_{4}^{-}+\mathrm{H}_{2} \stackrel{\oplus} {NO}_{2}\)…
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