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JEE Mains · Chemistry · STD 11 - 2. structure of atom

The minimum energy that must be possessed by photons in order to produce the photoelectric effect with platinum metal is \(....\,\times 10^{-19} \,J\) [Given: The threshold frequency of platinum is \(1.3\) \(\times 10^{15} \,s ^{-1}\) and \(h =6.6 \times 10^{-34} \,J \,s\).]

  1. A \(32.1\)
  2. B \(0.624\)
  3. C \(8.58\)
  4. D \(976\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(8.58\)

Step-by-step Solution

Detailed explanation

\(W = h v\) \(=6.6 \times 10^{-34} \times 1.3 \times 10^{15}\) \(=8.58 \times 10^{-19} \,J\)
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