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JEE Mains · Chemistry · STD 11 - 9. Hydricarbon

Consider the following chemical reaction. \(CH \equiv CH\xrightarrow[{{\text{(2) CO , HCl , AlC}}{{\text{l}}_3}}]{{{\text{(1) Red hot Fe tube, 873 K}}}}\) Product The number of \(sp ^{2}\) hybridized carbon atom(s) present in the product is ..........

  1. A \(3\)
  2. B \(9\)
  3. C \(4\)
  4. D \(7\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(7\)

Step-by-step Solution

Detailed explanation

In benzaldehyde total number of \(sp ^{2}{ }^{\prime} C ^{\prime}\) are 7 .
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