JEE Mains · Chemistry · STD 12 -1. Solution and colligative properties
\(2.7 \mathrm{Kg}\) of each of water and acetic acid are mixed, The freezing point of the solution will be \(-\mathrm{x}^{\circ} \mathrm{C}\). Consider the acetic acid does not dimerise in water, nor dissociates in water \(\mathrm{x}=\) _______ (nearest integer) [Given : Molar mass of water \(=18 \mathrm{~g} \mathrm{~mol}^{-1}\), acetic acid \(=60 \mathrm{~g} \mathrm{~mol}^{-1}\) ] \({ }^{\mathrm{K}_{\mathrm{f}}} \mathrm{H}_2 \mathrm{O}: 1.86 \mathrm{~K} \mathrm{~kg} \mathrm{~mol}^{-1}\) \(\mathrm{K}_{\mathrm{r}}\) acetic acid : \(3.90 \mathrm{~K} \mathrm{~kg} \mathrm{~mol}^{-1}\) freezing point: \(\mathrm{H}_2 \mathrm{O}=273 \mathrm{~K}\), acetic acid \(=290 \mathrm{~K}\) ]
- A \(31\)
- B \(35\)
- C \(37\)
- D \(40\)
Answer & Solution
Correct Answer
(A) \(31\)
Step-by-step Solution
Detailed explanation
As moles of water \(>\) moles of \(\mathrm{CH}_3 \mathrm{COOH}\) water is solvent. \(\mathrm{T}_{\mathrm{F}}^{\circ}-\left(\mathrm{T}_{\mathrm{F}}\right)_{\mathrm{S}}=\mathrm{K}_{\mathrm{F}} \times \mathrm{M}\)…
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