JEE Mains · Chemistry · STD 12 - 3. Chemical kinetics
Consider the following plots of log of rate constant \(\mathrm{k}(\log \mathrm{k})\) vs \(\frac{1}{\mathrm{~T}}\) for three different reactions. The correct order of activation energies of these reactions is which?
- A \(\mathrm{Ea}_2 \gt \mathrm{Ea}_1 \gt \mathrm{Ea}_3\)
- B \(\mathrm{Ea}_1 \gt \mathrm{Ea}_3 \gt \mathrm{Ea}_2\)
- C \(\mathrm{Ea}_1 \gt \mathrm{Ea}_2 \gt \mathrm{Ea}_3\)
- D \(\mathrm{Ea}_3 \gt \mathrm{Ea}_2 \gt \mathrm{Ea}_1\)
Answer & Solution
Correct Answer
(A) \(\mathrm{Ea}_2 \gt \mathrm{Ea}_1 \gt \mathrm{Ea}_3\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & \mathrm{K}=\mathrm{A} \mathrm{e}^{-\mathrm{E} a \mathrm{RT}} \\ & \operatorname{logk}=\log \mathrm{A}-\frac{\mathrm{Ea}}{2.303 \mathrm{RT}} \end{aligned}\) For graph between logk with \(\frac{1}{\mathrm{~T}}\)…
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