JEE Mains · Chemistry · STD 11 - 6.2. Equilibrium - II (icon Equilibrium)
Consider a weak base 'B' of \( pK_b = 5.699 \). 'x' mL of 0.02 M HCl and 'y' mL of 0.02 M weak base 'B' are mixed to make 100 mL of a buffer of pH 9 at \( 25^{\circ}C \).
The values of 'x' and 'y' respectively are:
(Given: \( \log 2=0.3010, \log 3=0.4771, \log 5=0.699 \))
- A x = 11.1, y = 88.9
- B x = 42.7, y = 57.3
- C x = 14.3, y = 85.7
- D x = 85.7, y = 14.3
Answer & Solution
Correct Answer
(C) x = 14.3, y = 85.7
Step-by-step Solution
Detailed explanation
\(\begin{array}{cccc} & HCl & + B \rightarrow BH ^{+}+ Cl ^{-} \\ & 0.02 M & 0.02 M & \\ & x~ml & y~ml & \\ t _{ f } & 0 & 0.02 y -0.02 x & 0.02 x \end{array}\) \(pOH = pK _{ b }+\log \left[\frac{\text { Salt }}{\text { Base }}\right]\)…
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