JEE Mains · Chemistry · STD 11 - 7. Redox reactions
Chlorine undergoes disproportionation in alkaline medium as shown below : \( \text { a } \mathrm{Cl}_2(\mathrm{~g})+\mathrm{b} \mathrm{OH}^{-}(\mathrm{aq}) \rightarrow \mathrm{c} \mathrm{ClO}^{-}(\mathrm{aq})+\mathrm{d} \mathrm{Cl}^{-}(\mathrm{aq}) +\mathrm{e} \mathrm{H}_2 \mathrm{O}(l)\) The values of \(a, \ b,\ c\) and \(d\) in a balanced redox reaction are respectively :
- A \(1\), \(2\), \(1\) and \(1\)
- B \(2\), \(2\), \(1\) and \(3\)
- C \(3\),\(4\),\(4\) and \(2\)
- D \(2\), \(4\), \(1\) and \(3\)
Answer & Solution
Correct Answer
(A) \(1\), \(2\), \(1\) and \(1\)
Step-by-step Solution
Detailed explanation
\(\Rightarrow \mathrm{Cl}_2+2 \overline{\mathrm{O}} \mathrm{H} \longrightarrow \mathrm{Cl}^{-}+\mathrm{ClO}^{-}+\mathrm{H}_2 \mathrm{O}\)
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