JEE Mains · Chemistry · STD 11 - 2. structure of atom
If \(m\) and \(e\) are the mass and charge of the revolving electron in the orbit of radius \(r\) for hydrogen atom, the total energy of the revolving electron will be
- A \(\frac{1}{2}\,\frac{{{e^2}}}{r}\)
- B \( - \frac{{{e^2}}}{r}\)
- C \(\frac{{m{e^2}}}{r}\)
- D \(-\frac{1}{2}\,\frac{{{e^2}}}{r}\)
Answer & Solution
Correct Answer
(D) \(-\frac{1}{2}\,\frac{{{e^2}}}{r}\)
Step-by-step Solution
Detailed explanation
Total energy of a revolving electron is the sum of its kinetic and potential energy. Total energy \(= K.E. + P. E.\) \( = \frac{{{e^2}}}{{2r}} + \left( { - \frac{{{e^2}}}{r}} \right) = - \frac{{{e^2}}}{{2r}}\)
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