JEE Mains · Chemistry · STD 12 - 3. Chemical kinetics
The equation \(k =\left(6.5 \times 10^{12} \,s ^{-1}\right) e ^{-26000 K / T }\) is followed for the decomposition of compound \(A\). The activation energy for the reaction is \(.....\,kJ\) \(mol ^{-1}\). [nearest integer] (Given: \(R =8.314 \,J\, K ^{-1}\, mol ^{-1}\) )
- A \(2160\)
- B \(216\)
- C \(26\)
- D \(674\)
Answer & Solution
Correct Answer
(B) \(216\)
Step-by-step Solution
Detailed explanation
\(K = Ae ^{- Ea / RT }=\left(6.5 \times 10^{12} s ^{-1}\right) e ^{-26000\, K / T }\) \(\frac{ Ea }{8.314}=26000\) \(Ea =216.164 \,kJ / mol\)
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