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JEE Mains · Chemistry · STD 12 - 3. Chemical kinetics

The equation \(k =\left(6.5 \times 10^{12} \,s ^{-1}\right) e ^{-26000 K / T }\) is followed for the decomposition of compound \(A\). The activation energy for the reaction is \(.....\,kJ\) \(mol ^{-1}\). [nearest integer] (Given: \(R =8.314 \,J\, K ^{-1}\, mol ^{-1}\) )

  1. A \(2160\)
  2. B \(216\)
  3. C \(26\)
  4. D \(674\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(216\)

Step-by-step Solution

Detailed explanation

\(K = Ae ^{- Ea / RT }=\left(6.5 \times 10^{12} s ^{-1}\right) e ^{-26000\, K / T }\) \(\frac{ Ea }{8.314}=26000\) \(Ea =216.164 \,kJ / mol\)
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