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JEE Mains · Chemistry · STD 11 - 2. structure of atom

Based on Heisenberg's uncertainty principle, the uncertainty in the velocity of the electron to be found within an atomic nucleus of diameter \(10^{-15} \mathrm{~m}\) is _______ \(\times 10^9 \mathrm{~ms}^{-1}\). (nearest integer) [Given : mass of electron \(=9.1 \times 10^{-31} \mathrm{~kg}\), Plank's constant \((\mathrm{h})=6.626 \times 10^{-34} \mathrm{JS}\) ] (Value of \(\pi=3.14\) )

  1. A \(12\)
  2. B \(65\)
  3. C \(58\)
  4. D \(20\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(58\)

Step-by-step Solution

Detailed explanation

\( \mathrm{m} \Delta \mathrm{V} \cdot \Delta \mathrm{x}=\frac{\mathrm{h}}{4 \pi} \) \(\Delta \mathrm{V} \)\( =\frac{6.626 \times 10^{-34}}{9.1 \times 10^{-31} \times 10^{-15} \times 4 \times 3.14} \) \( =57.97 \times 10^{+9} \mathrm{~m} / \mathrm{sec}\)
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