JEE Mains · Chemistry · STD 12 - 2. Electrochemistry
At \(298\text{ K}\), the molar conductivity of \(x\%\) (w/w) \(MX\) solution (aqueous) is \(123.5\text{ S cm}^2\text{ mol}^{-1}\). The conductance of same solution is \(1.9 \times 10^{-3}\text{ S}\). The value of \(x\) is _______ \(\times 10^{-2}\).
(Given : cell constant \(= 1.3\text{ cm}^{-1}\); molar mass of \(MX\) is \(75\text{ g mol}^{-1}\), density of aqueous solution of \(MX\) at \(298\text{ K}\) is \(1.0\text{ g mL}^{-1}\))
- A 10
- B 15
- C 20
- D 25
Answer & Solution
Correct Answer
(B) 15
Step-by-step Solution
Detailed explanation
The conductivity (specific conductance), \(\kappa\), is given by the product of conductance and cell constant: \(\kappa = G \times G^*\) \(\kappa = 1.9 \times 10^{-3} \text{ S} \times 1.3 \text{ cm}^{-1} = 2.47 \times 10^{-3} \text{ S cm}^{-1}\) The molar conductivity,…
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