JEE Mains · Chemistry · STD 12 - 4. d and f- block elements
Cerium \((IV)\) has a noble gas configuration. Which of the following is correct statement about it?
- A It will not prefer to undergo redox reactions.
- B It will prefer to gain electron and act as an oxidizing agent
- C It will prefer to give away an electron and behave as reducing agent
- D It acts as both, oxidizing and reducing agent.
Answer & Solution
Correct Answer
(B) It will prefer to gain electron and act as an oxidizing agent
Step-by-step Solution
Detailed explanation
Cerium exists in two different oxidation state \(+3\), \(+4\) \(Ce ^{+4}+ e ^{-} \rightarrow Ce ^{3+} \,\quad\quad\,\,\, E ^{0}=+1.61 \,V\) \(Ce ^{+3}+3 e ^{-} \rightarrow Ce \quad\quad\,\,\, E ^{0}=-2.336 \,V\) It shows \(Ce ^{+4}\) acts as a strong oxidising agent \(\&\)…
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