JEE Mains · Physics · STD 11 - 7. gravitation
Two satellites, \(A\) and \(B,\) have masses \(m\) and \(2\,m\) respectively. \(A\) is in a circular orbit of radius \(R,\) and \(B\) is in a circular orbit of radius \(2R\) around the earth. The ratio of their kinetic energies, \(K.E._A / K.E._B ,\) is
- A \(\frac {1}{2}\)
- B \(1\)
- C \(2\)
- D \(\sqrt {\frac {1}{2}}\)
Answer & Solution
Correct Answer
(B) \(1\)
Step-by-step Solution
Detailed explanation
\(K{E_A} = \frac{1}{2}m\left( {\frac{{GM}}{R}} \right)\) \(K{E_B} = \frac{1}{2}\left( {2m} \right)\left( {\frac{{GM}}{{2R}}} \right)\) \( \Rightarrow \frac{{K{E_A}}}{{K{E_B}}} = 1\)
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