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JEE Mains · Chemistry · STD 11 - 1. Some basic concept of chemistry

The density of ' \(x\) ' \(\mathrm{M}\) solution (' \(\mathrm{x}\) ' molar) of \(\mathrm{NaOH}\) is \(1.12 \mathrm{~g} \mathrm{~mL}^{-1}\). while in molality, the concentration of the solution is \(3 \mathrm{~m}\) ( \(3 \mathrm{molal})\). Then \(\mathrm{x}\) is _______. (Given : Molar mass of \(\mathrm{NaOH}\) is \(40 \mathrm{~g} / \mathrm{mol}\) )

  1. A \(3.5\)
  2. B \(3.0\)
  3. C \(3.8\)
  4. D \(2.8\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(3.0\)

Step-by-step Solution

Detailed explanation

\(\text { Molality }=\frac{1000 \times \mathrm{M}}{1000 \times \mathrm{d}-\mathrm{M} \times(\mathrm{Mw})_{\text {solute }}}\) \(3=\frac{1000 \times \mathrm{x}}{1000 \times 1.12-(\mathrm{x} \times 40)}\) \(\mathrm{x}=3\)
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