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JEE Mains · Chemistry · STD 11 - 5. Thermodynamics and thermochemistry

At \(25^{\circ} C\) and \(1\, atm\) pressure, the enthalpy of combustion of benzene\(_{(l)}\) and acetylene\(_{(g)}\) are \(-3268 \,kJ\, mol ^{-1}\) and \(-1300\, kJ\, mol ^{-1}\), respectively. The change in enthalpy for the reaction \(3 C _{2} {H _{2}}_{(g)} \rightarrow C _{6} {H _{6}}_{(l)}\), is \(.....\,kJ \,mol ^{-1}\)

  1. A \(+\,324\)
  2. B \(+\,632\)
  3. C \(-\,632\)
  4. D \(-\,324\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(-\,632\)

Step-by-step Solution

Detailed explanation

\(\Delta H =\sum \Delta H _{\text {Combustion }}\) (Reactant) \(-\sum \Delta H _{\text {Combustion }}\) (Product) \(=3 \times(-1300)\,-\,[-3268]\) \(=-632\, kJ\, mol ^{-1}\)
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