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JEE Mains · Physics · STD 11 - 3.2 motion in plane

A ball is projected with kinetic energy \(E\), at an angle of \(60^{\circ}\) to the horizontal. The kinetic energy of this ball at the highest point of its flight will become.

  1. A \(Zero\)
  2. B \(\frac{E}{2}\)
  3. C \(\frac{E}{4}\)
  4. D \(E\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(\frac{E}{4}\)

Step-by-step Solution

Detailed explanation

\(E =\frac{1}{2} mu ^{2}\) At Highest point, Velocity \(V = u \cos 60^{\circ}=\frac{ u }{2}\) \(\therefore K E \text { at topmost point }=\frac{1}{2} m \left(\frac{ u }{2}\right)^{2}=\frac{E}{4}\)
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