ExamBro
ExamBro
JEE Mains · Physics · STD 11 - Motion in plane
  • JEE Mains 2022
  • Medium
  • MCQ

A ball is projected with kinetic energy \(E\), at an angle of \(60^{\circ}\) to the horizontal. The kinetic energy of this ball at the highest point of its flight will become.

Pick an option to check your answer.
Verified Solution

Answer & Solution

Correct Answer

(C) \(\frac{E}{4}\)

Step-by-step Solution

Detailed explanation

\(E =\frac{1}{2} mu ^{2}\)

At Highest point, Velocity \(V = u \cos 60^{\circ}=\frac{ u }{2}\)

\(\therefore K E \text { at topmost point }=\frac{1}{2} m \left(\frac{ u }{2}\right)^{2}=\frac{E}{4}\)

Same subject
Explore more questions on app