JEE Mains · Chemistry · STD 11 - 8.3. Organic chemistry purification and characterization
Acidic ferric chloride solution on treatment with excess of potassium ferrocyanide gives a Prussian blue coloured colloidal species. It is :
- A \(\mathrm{Fe}_{4}\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]_{3}\)
- B \(\mathrm{K}_{5} \mathrm{Fe}\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]_{2}\)
- C \(\mathrm{HFe}\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]\)
- D \(\mathrm{KFe}\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]\)
Answer & Solution
Correct Answer
(D) \(\mathrm{KFe}\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]\)
Step-by-step Solution
Detailed explanation
\(\mathrm{FeCl}_{3}+\mathrm{K}_{4}\left[\mathrm{Fe}(\mathrm{CN})_{6}\right](\text { excess })\) \(\quad\quad\quad\downarrow\) \(\mathrm{K} \mathrm{Fe}\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]\) Colloidal species
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