JEE Mains · Chemistry · STD 11 - 4. Chemical bonding and molecular structure
Arrange the following compounds in increasing order of their dipole moment : \(\mathrm{HBr}, \mathrm{H}_2 \mathrm{~S}, \mathrm{NF}_3\) and \(\mathrm{CHCl}_3\)
- A \(\mathrm{H}_2 \mathrm{~S} \lt \mathrm{HBr} \lt \mathrm{NF}_3 \lt \mathrm{CHCl}_3\)
- B \(\mathrm{NF}_3 \lt \mathrm{HBr} \lt \mathrm{H}_2 \mathrm{~S} \lt \mathrm{CHCl}_3\)
- C \(\mathrm{HBr} \lt \mathrm{H}_2 \mathrm{~S} \lt \mathrm{NF}_3 \lt \mathrm{CHCl}_3\)
- D \(\mathrm{CHCl}_3 \lt \mathrm{NF}_3 \lt \mathrm{HBr} \lt \mathrm{H}_2 \mathrm{~S}\)
Answer & Solution
Correct Answer
(B) \(\mathrm{NF}_3 \lt \mathrm{HBr} \lt \mathrm{H}_2 \mathrm{~S} \lt \mathrm{CHCl}_3\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & \mu_{\mathrm{HBr}}=0.78 \mathrm{D} \\ & \mu_{\mathrm{H}_2 \mathrm{~S}}=0.95 \mathrm{D} \\ & \mu_{\mathrm{NF}_3}=0.24 \mathrm{D} \\ & \mu_{\mathrm{CHCl}_3}=1.01 \mathrm{D} \end{aligned}\) Hence dipole moment of…
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