JEE Mains · Chemistry · STD 11 - 1. Some basic concept of chemistry
An unknown chlorohydrocarbon has \(3.55\%\) of chlorine. If each molecule of the hydrocarbon has one chlorine atom only, chlorine atoms present in \(1\,g\) of chlorohydrocarbon are (Atomic wt. of \(Cl = 35.5\,u;\) Avogadro constant \(= 6.023 \times 10^{23}\,mol^{- 1}\) )
- A \(6.023 \times {10^9}\)
- B \(6.023 \times {10^{23}}\)
- C \(6.023 \times {10^{21}}\)
- D \(6.023 \times {10^{20}}\)
Answer & Solution
Correct Answer
(D) \(6.023 \times {10^{20}}\)
Step-by-step Solution
Detailed explanation
Given percentage of chlorine in an hydrocarbon \(= 3.55\%\) i,e., \(100\,g\) of chlorohydrocarbon has \(3.55\,g\) of chlorine. \(1\,g\) of chlorohydrocarbon will have \(\frac{{3.55}}{{100}} = 0.0355\,g\) of chlorine. Atomic wt. of \(Cl = 35.5\,g/mol\) Number of moles of \(Cl\)…
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