JEE Mains · Chemistry · STD 12 - 4. d and f- block elements
Match List - I with List - II.
| List - I (Transition metal ion) | List - II (Spin only magnetic moment (B.M.)) | ||
| (A) | Ti3+ | (I) | 3.87 |
| (B) | V2+ | (II) | 0.00 |
| (C) | Ni2+ | (III) | 1.73 |
| (D) | Sc3+ | (IV) | 2.84 |
Choose the correct answer from the options given below :
- A (A) \(-(\mathrm{III}),(\mathrm{B})-(\mathrm{I}),(\mathrm{C})-(\mathrm{IV}),(\mathrm{D})-(\mathrm{II})\)
- B (A) \(-(\mathrm{III}),(\mathrm{B})-(\mathrm{I}),(\mathrm{C})-(\mathrm{II}),(\mathrm{D})-(\mathrm{IV})\)
- C (A) \(-(\mathrm{IV}),(\mathrm{B})-(\mathrm{II}),(\mathrm{C})-(\mathrm{III}),(\mathrm{D})-(\mathrm{I})\)
- D \((\mathrm{A})-(\mathrm{II}),(\mathrm{B})-(\mathrm{IV}),(\mathrm{C})-(\mathrm{I}),(\mathrm{D})-(\mathrm{III})\)
Answer & Solution
Correct Answer
(A) (A) \(-(\mathrm{III}),(\mathrm{B})-(\mathrm{I}),(\mathrm{C})-(\mathrm{IV}),(\mathrm{D})-(\mathrm{II})\)
Step-by-step Solution
Detailed explanation
\begin{array}{lc}\mathrm{Sc}^{+3}=3 \mathrm{~d}^{\mathrm{o}} & \therefore \mu_{\text {spin }}=0 \\ \mathrm{~V}^{+2}=3 \mathrm{~d}^3 & \therefore \mu_{\text {spin }}=3.87 \mathrm{~B} \cdot \mathrm{M} . \\ \mathrm{Ni}^{+2}=3 \mathrm{~d}^8 & \therefore \mu_{\text {spin }}=2.84…
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