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JEE Mains · Chemistry · STD 12 - 4. d and f- block elements

Match List - I with List - II.
List - I
(Transition metal ion)
List - II
(Spin only magnetic moment (B.M.))
(A)Ti3+(I)3.87
(B)V2+(II)0.00
(C)Ni2+(III)1.73
(D)Sc3+(IV)2.84

Choose the correct answer from the options given below :

  1. A (A) \(-(\mathrm{III}),(\mathrm{B})-(\mathrm{I}),(\mathrm{C})-(\mathrm{IV}),(\mathrm{D})-(\mathrm{II})\)
  2. B (A) \(-(\mathrm{III}),(\mathrm{B})-(\mathrm{I}),(\mathrm{C})-(\mathrm{II}),(\mathrm{D})-(\mathrm{IV})\)
  3. C (A) \(-(\mathrm{IV}),(\mathrm{B})-(\mathrm{II}),(\mathrm{C})-(\mathrm{III}),(\mathrm{D})-(\mathrm{I})\)
  4. D \((\mathrm{A})-(\mathrm{II}),(\mathrm{B})-(\mathrm{IV}),(\mathrm{C})-(\mathrm{I}),(\mathrm{D})-(\mathrm{III})\)
Verified Solution

Answer & Solution

Correct Answer

(A) (A) \(-(\mathrm{III}),(\mathrm{B})-(\mathrm{I}),(\mathrm{C})-(\mathrm{IV}),(\mathrm{D})-(\mathrm{II})\)

Step-by-step Solution

Detailed explanation

\begin{array}{lc}\mathrm{Sc}^{+3}=3 \mathrm{~d}^{\mathrm{o}} & \therefore \mu_{\text {spin }}=0 \\ \mathrm{~V}^{+2}=3 \mathrm{~d}^3 & \therefore \mu_{\text {spin }}=3.87 \mathrm{~B} \cdot \mathrm{M} . \\ \mathrm{Ni}^{+2}=3 \mathrm{~d}^8 & \therefore \mu_{\text {spin }}=2.84…

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