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JEE Mains · Chemistry · STD 12 - 5. Co-ordination chemistry
The total number of possible isomers for squareplanar \([Pt(Cl)(NO_2)(NO_3)(SCN)]^{2-}\) is:
- A \(16\)
- B \(12\)
- C \(8\)
- D \(24\)
Answer & Solution
Correct Answer
(B) \(12\)
Step-by-step Solution
Detailed explanation
The square planar complex of the type \([Mabcd]^{n±}\), where all four ligands are different, has \(3\) geometrical isomers. But if one of the ligands is ambidentate, then \(2\times3\, = 6\) geometrical isomers are possible. But if two ligands are ambidentate, then…
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