JEE Mains · Chemistry · STD 12 -1. Solution and colligative properties
An aqueous solution of volume \(300\,cm ^3\) contains \(0.63\,g\) of protein. The osmotic pressure of the solution at \(300\,K\) is \(1.29\,mbar\). The molar mass of the protein is \(.........\,g\,mol ^{-1}\) Given : \(R =0.083\,L\,bar\,K ^{-1} mol ^{-1}\)
- A \(40536\)
- B \(40537\)
- C \(40535\)
- D \(40538\)
Answer & Solution
Correct Answer
(C) \(40535\)
Step-by-step Solution
Detailed explanation
\(\because \pi= CRT\) \(\pi=\frac{n}{V} R T\) \(\pi=\frac{\omega}{V} \frac{R T}{M}\) \(M=\frac{\omega R T}{\pi \times V}\) \(M=\frac{0.63 \times 0.083 \times 300}{1.29 \times 10^{-3} \times 300 \times 10^{-3}}\) \(M=40535\,gm / moL\)
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