JEE Mains · Chemistry · STD 12 - 3. Chemical kinetics
A reaction has a half life of \(1\,min.\) The time required for \(99.9\, \%\) completion of the reaction is ......... \(min.\) (Round off to the Nearest integer) [Use : \(\ln\, 2=0.69, \ln \,10=2.3]\)
- A \(4\)
- B \(15\)
- C \(11\)
- D \(10\)
Answer & Solution
Correct Answer
(D) \(10\)
Step-by-step Solution
Detailed explanation
\(\frac{ t _{99.996}}{ t _{50 \%}}=\frac{\frac{1}{ K } \ln \frac{100}{0.1}}{\frac{1}{ K } \ln 2}\) \(=\frac{\ln 1000}{\ln 2} \times t _{50 \%}\) \(=\frac{3 \ln 10}{\ln 2} \times 1\) \(=\frac{3 \times 2.3}{0.69}=10\)
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