JEE Mains · Chemistry · STD 12 - 4. d and f- block elements
Consider the following reaction \(\mathrm{MnO}_2+\mathrm{KOH}+\mathrm{O}_2 \rightarrow \mathrm{A}+\mathrm{H}_2 \mathrm{O} .\) Product ' \(A\) ' in neutral or acidic medium disproportionate to give products ' \(\mathrm{B}\) ' and ' \(\mathrm{C}\) ' along with water. The sum of spin-only magnetic moment values of \(B\) and \(C\) is _______ \(BM\). (nearest integer) (Given atomic number of \(\mathrm{Mn}\) is \(25\) )
- A \(3\)
- B \(4\)
- C \(5\)
- D \(7\)
Answer & Solution
Correct Answer
(B) \(4\)
Step-by-step Solution
Detailed explanation
\(\mathrm{MnO}_2+\mathrm{KOH}+\mathrm{O}_2 \rightarrow \mathrm{K}_2 \mathrm{MnO}_4+\mathrm{H}_2 \mathrm{O}\) \((A)\) \({K}_2 \mathrm{MnO}_4 \xrightarrow{\text { Neutral/acidic solution }} \mathrm{KMnO}_4+\mathrm{MnO}_2\) \(\mathrm{Mn}^{+4}:-[\mathrm{Ar}] 3 \mathrm{~d}^3\)…
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