JEE Mains · Chemistry · STD 11 - 4. Chemical bonding and molecular structure
Given below are two statements :
Statement I : The number of compounds among SO\(_2\), SO\(_3\), SF\(_4\), SF\(_6\) and H\(_2\)S in which sulphur does not obey the Octet rule is \(3\).
Statement II : Among [H\(_2\)O, ClF\(_3\), SF\(_4\)], [NH\(_3\), BrF\(_5\), SF\(_4\)], [BrF\(_5\), ClF\(_3\), XeF\(_4\)] and [XeF\(_4\), ClF\(_3\), H\(_2\)O], the number of sets in which all the molecules have one lone pair of electrons on the central atom is \(1\).
In the light of the above statements, choose the correct answer from the options given below :
- A Both Statement I and Statement II are true
- B Both Statement I and Statement II are false
- C Statement I is true but Statement II is false
- D Statement I is false but Statement II is true
Answer & Solution
Correct Answer
(D) Statement I is false but Statement II is true
Step-by-step Solution
Detailed explanation
Statement I: Number of compounds in which sulphur does not follow the octet rule (from \(SO_2\), \(SO_3\), \(SF_4\), \(SF_6\) and \(H_2S\)). \(SO_2\): The formal-charge-minimised structure \(O=S=O\) places \(10\) electrons around sulphur (expanded octet). \(SO_3\): With three…
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