JEE Mains · Chemistry · STD 11 - 6.2. Equilibrium - II (icon Equilibrium)
Arrange the following resultant mixtures in increasing order of their pH values
A. \(10\) mL \(0.2\) M Ca(OH)\(_2\) + \(25\) mL \(0.1\) M HCl
B. \(10\) mL \(0.01\) M H\(_2\)SO\(_4\) + \(10\) mL \(0.01\) M Ca(OH)\(_2\)
C. \(10\) mL \(0.1\) M H\(_2\)SO\(_4\) + \(10\) mL \(0.1\) M KOH
Choose the correct answer from the options given below:
- A \(B < C < A\)
- B \(C < A < B\)
- C \(C < B < A\)
- D \(A < C < B\)
Answer & Solution
Correct Answer
(C) \(C < B < A\)
Step-by-step Solution
Detailed explanation
For mixture A: Millimoles of OH\(^{-}\) = \(10 \times 0.2 \times 2 = 4\) Millimoles of H\(^{+}\) = \(25 \times 0.1 \times 1 = 2.5\) Remaining OH\(^{-}\) = \(4 - 2.5 = 1.5\) mmol The solution is basic, so pH \(> 7\). For mixture B: Millimoles of H\(^{+}\) =…
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