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JEE Mains · Chemistry · STD 11 - 1. Some basic concept of chemistry
\(10\, mL\) of \(2\,(M)\, NaOH\) solution is added to \(200\, mL\) of \(0.5\, (M)\) of \(NaOH\) solution. What is the final concentration ?............. \(\mathrm{M}\)
- A \(0.57\)
- B \(5.7\)
- C \(11.4\)
- D \(1.14\)
Answer & Solution
Correct Answer
(A) \(0.57\)
Step-by-step Solution
Detailed explanation
From molarity equation \({M_1}{V_1} + {M_2}{V_2} = M{V_{(total)}}\) \(2 \times \frac{{10}}{{1000}} + 0.5 \times \frac{{200}}{{1000}} = M \times \frac{{210}}{{1000}}\) \(120 = M \times 210\) \(M = \frac{{120}}{{210}} = 0.57\,M\)
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