JEE Mains · Chemistry · STD 12 - 3. Chemical kinetics
An organic compound undergoes first order decomposition. If the time taken for the \(60 \,\%\) decomposition is \(540\,s\), then the time required for \(90\,\%\) decomposition will be is \(..........s\). (Nearest integer). Given : \(\ln 10=2.3 ; \log 2=0.3\)
- A \(1351\)
- B \(1352\)
- C \(1353\)
- D \(1350\)
Answer & Solution
Correct Answer
(D) \(1350\)
Step-by-step Solution
Detailed explanation
\(\frac{t_1}{t_2}=\frac{\frac{1}{ K } \ln \frac{ a _0}{0.4 a _0}}{\frac{1}{ K } \ln \frac{ a _0}{0.1 a _0}}\) \(\frac{540}{ t _2}=\frac{\ln \frac{10}{4}}{\ln 10}\) \(\frac{540}{ t _2}=\frac{\log 10-\log 4}{\log 10}\) \(\frac{540}{ t _2}=\frac{1-0.6}{1}\)…
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