JEE Mains · Chemistry · STD 11 - 4. Chemical bonding and molecular structure
The correct order of bond dissociation energy among \(N_2, O_2, O_2^-\) is shown in which of the following arrangements?
- A \(N_2 > O_2^- > O_2\)
- B \(O_2^- > O_2 > N_2\)
- C \(N_2 > O_2 > O_2^-\)
- D \(O_2 > O_2^- > N_2\)
Answer & Solution
Correct Answer
(C) \(N_2 > O_2 > O_2^-\)
Step-by-step Solution
Detailed explanation
The bond order of \(N_2,\) \(O_2,\) and \(O_2^-\) are respectively \(3,2\) and \(1.5\) Since higher bond order implies higher bond dissociation energy hence the correct orde will be \(N_2 > O_2 > O_2^-\)
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