JEE Mains · Chemistry · STD 11 - 1. Some basic concept of chemistry
For the given reaction:
\(CaCO_{3} + 2HCl \to CaCl_{2} + H_{2}O + CO_{2}\)
If 90 g \(CaCO_{3}\) is added to 300 mL of HCl which contains 38.55% HCl by mass and has density \(1.13 g mL^{-1}\) then which of the following option is correct?
[Given molar mass of H, Cl, Ca and O are 1, 35.5, 40 and \(16 g mol^{-1}\) respectively]
- A 64.97 g of HCl remains unreacted
- B 32.85 g of \(CaCO_{3}\) remains unreacted
- C 97.30 g of HCl reacted
- D 60.32 g of HCl remains unreacted
Answer & Solution
Correct Answer
(A) 64.97 g of HCl remains unreacted
Step-by-step Solution
Detailed explanation
Density of HCl solution \(( d )=1.13 g / ml\) \(V =300 ml\) Wt. of HCl solution \(=339 g\) Wt. of \(HCl =339 \times \frac{38.55}{100}=130.68 g\) (LR) \(CaCO_3+2 HCl \rightarrow CaCl_2+H_2 O+CO_2\) \(\frac{90}{100} \quad \frac{130.68}{36.5}\) \(=0.90 mole \quad=3.58 mole\) Moles…
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