JEE Mains · Chemistry · STD 11 - 1. Some basic concept of chemistry
x mg of pure HCl was used to make an aqueous solution. 25.0 mL of \(0.1 M Ba ( OH )_2\) solution is used when the HCl solution was titrated against it. The numerical value of x is _________ \(\times 10^{-1}\). (Nearest integer)
Given : Molar mass of HCl and \(Ba ( OH )_2\) are 36.5 and \(171.0 g mol ^{-1}\) respectively.
- A 182.5
- B 1825
- C 365
- D 91.25
Answer & Solution
Correct Answer
(B) 1825
Step-by-step Solution
Detailed explanation
\(Ba ( OH )_{2( aq )}+2 HCl _{( aq )} \rightarrow BaCl _{2( aq )}+2 H _2 O _{(\ell)}\) 2.5 mmole \(\quad\)5mmole wt of \(HCl =5 \times 36.5\) (milligram) = 182.5 (milligram) Hence \(x =1825\).
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