JEE Mains · Chemistry · STD 11 - 5. Thermodynamics and thermochemistry
A gas (Molar mass \(=280\,g\,mol ^{-1}\) ) was burnt in excess \(O _{2}\) in a constant volume calorimeter and during combustion the temperature of calorimeter increased from \(298.0 K\) to \(298.45\,K\). If the heat capacity of calorimeter is \(2.5\,kJ\,K ^{-1}\) and enthalpy of combustion of gas is \(9\,kJ\,mol ^{-1}\) then amount of gas burnt is \(......g\). (Nearest Integer)
- A \(35\)
- B \(34\)
- C \(33\)
- D \(32\)
Answer & Solution
Correct Answer
(A) \(35\)
Step-by-step Solution
Detailed explanation
Let \(x g\) is burnt \(\text { moles }=\frac{ x }{280}\) heat released by \(\frac{ x }{280}\) mole \(=2.5 \times 0.45\,kJ\) heat released by \(1\,mole\) \(=\frac{2.5 \times 0.45 \times 280}{ x } kJ\) \(\Delta H =\Delta U +\Delta ngRT\) \(\Delta H \simeq \Delta U\)…
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