JEE Mains · Chemistry · STD 11 - 6.1. Equilibrium - 1 (chemical Equilibrium)
For the following gas phase equilibrium reaction at constant temperature,
\(NH_3(g) \rightleftharpoons \frac{1}{2} N_2(g)+\frac{3}{2} H_2(g)\)
If the total pressure is \(\sqrt{3} \) atm and the pressure equilibrium constant \(\left( K _{ p }\right)\) is 9 atm , then the degree of dissociation is given as \(\left(x \times 10^{-2}\right)^{-1 / 2}\).
The value of \(x\) is __________ (Nearest integer)
- A 100
- B 125
- C 150
- D 200
Answer & Solution
Correct Answer
(B) 125
Step-by-step Solution
Detailed explanation
\(NH _{3(g)} \rightleftharpoons \frac{1}{2} N_{2(g)}+\frac{3}{2} H _{2(g)}\) \(t=0\)\(\quad\)1mole\(\quad\quad\)—\(\quad\quad\)— \(t = t _{ eq }\)\(\quad\)\(1-\alpha\)\(\quad\)\(\alpha / 2\)\(\quad\)\(3 \alpha / 2\)…
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