JEE Mains · Chemistry · STD 11 - 4. Chemical bonding and molecular structure
A diatomic molecule has a dipole moment of \(1.2 D\). If the bond distance is \(1 \mathring A\), then fractional charge on each atom is _______ \(\times 10^{-1}\) esu. (Given \(1 \mathrm{D}=10^{-18}\) esu \(\mathrm{cm}\) )
- A \(0\)
- B \(5\)
- C \(1\)
- D \(-1\)
Answer & Solution
Correct Answer
(A) \(0\)
Step-by-step Solution
Detailed explanation
\(\mu=1.2 \mathrm{D}=\mathrm{q} \times \mathrm{d}\) \(\Rightarrow 1.2 \times 10^{-10} \mathrm{esu} A=\mathrm{q} \times 1 A\) \(\therefore \mathrm{q}=1.2 \times 10^{-10} \text { esu }\)
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