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JEE Mains · Chemistry · STD 11 - 4. Chemical bonding and molecular structure

Which of the following statement is true with respect to \(\mathrm{H}_2 \mathrm{O}, \mathrm{NH}_3\) and \(\mathrm{CH}_4\) ?
A. The central atoms of all the molecules are \(\mathrm{sp}^3\) hybridized.
B. The \(\mathrm{H}-\mathrm{O}-\mathrm{H}, \mathrm{H}-\mathrm{N}-\mathrm{H}\) and \(\mathrm{H}-\mathrm{C}-\mathrm{H}\) angles in the above molecules are \(104.5^{\circ}, 107.5^{\circ}\) and \(109.5^{\circ}\), respectively.
C. The increasing order of dipole moment is \(\mathrm{CH}_4 \lt \mathrm{NH}_3 \lt \mathrm{H}_2 \mathrm{O}\).
D. Both \(\mathrm{H}_2 \mathrm{O}\) and \(\mathrm{NH}_3\) are Lewis acids and \(\mathrm{CH}_4\) is a Lewis base.
E. A solution of \(\mathrm{NH}_3\) in \(\mathrm{H}_2 \mathrm{O}\) is basic. In this solution \(\mathrm{NH}_3\) and \(\mathrm{H}_2 \mathrm{O}\) act as Lowry-Bronsted acid and base respectively.
Choose the correct answer from the options given below:

  1. A A, B and C Only
  2. B A, D and E Only
  3. C C, D and E Only
  4. D A, B, C and E Only
Verified Solution

Answer & Solution

Correct Answer

(A) A, B and C Only

Step-by-step Solution

Detailed explanation

Dipole moment \(\quad \mathrm{H}_2 \mathrm{O}>\mathrm{NH}_3>\mathrm{CH}_4\) \(\mathrm{H}_2 \mathrm{O} \& \mathrm{NH}_3\) are Lewis Bases \(\mathrm{NH}_3\) act as Lowry- Bronsted base Hence, A, B & C are correct
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