JEE Mains · Chemistry · STD 11 - 2. structure of atom
In a multielectron atom, which of the following orbitals described by three quantum numbers will have same energy in absence of electric and magnetic fields?
A. \(\mathrm{n}=1, \mathrm{l}=0, \mathrm{~m}_1=0\)
B. \(\mathrm{n}=2, \mathrm{l}=0, \mathrm{~m}_1=0\)
C. \(\mathrm{n}=2, \mathrm{l}=1, \mathrm{~m}_1=1\)
D. \(\mathrm{n}=3, \mathrm{l}=2, \mathrm{~m}_1=1\)
E. \(\mathrm{n}=3, \mathrm{l}=2, \mathrm{~m}_1=0\)
Choose the correct answer from the options given below:
- A B and C Only
- B A and B Only
- C C and D Only
- D D and E Only
Answer & Solution
Correct Answer
(D) D and E Only
Step-by-step Solution
Detailed explanation
\begin{array}{lc} \mathrm{A}: \mathrm{n}=1, \ell=0, \mathrm{~m}_{\ell}=0 & 1 \mathrm{~s} \\ \mathrm{B}: \mathrm{n}=2, \ell=0, \mathrm{~m}_{\ell}=0 & 2 \mathrm{~s} \\ \mathrm{C}: \mathrm{n}=2, \ell=1, \mathrm{~m}_{\ell}=1 & 3 \mathrm{p} \\ \mathrm{D}: \mathrm{n}=3, \ell=2,…
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