JEE Mains · Chemistry · STD 12 -1. Solution and colligative properties
Sea water, which can be considered as a 6 molar \((6 \mathrm{M})\) solution of NaCl , has a density of \(2 \mathrm{~g} \mathrm{~mL}^{-1}\). The concentration of dissolved oxygen \(\left(\mathrm{O}_2\right)\) in sea water is 5.8 ppm. Then the concentration of dissolved oxygen \(\left(\mathrm{O}_2\right)\) in sea water, is \(\mathrm{x} \times 10^{-4} \mathrm{~m}\). \(\mathrm{x}=\) _______. (Nearest integer)
Given: Molar mass of NaCl is \(58.5 \mathrm{~g} \mathrm{~mol}^{-1}\) Molar mass of \(\mathrm{O}_2\) is \(32 \mathrm{~g} \mathrm{~mol}^{-1}\)
- A 1
- B 2
- C 3
- D 4
Answer & Solution
Correct Answer
(B) 2
Step-by-step Solution
Detailed explanation
Sea water is 6 Molar in NaCl , So 1000 ml of sea water contains 6 mol of NaCl. mass of solution \(=\) Volume \(\times\) density \(=1000 \times 2\) mass of solution \(=2000 \mathrm{~g}\)…
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