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JEE Mains · Chemistry · STD 11 - 6.2. Equilibrium - II (icon Equilibrium)

\(3 \;g\) of acetic acid is added to \(250\; \mathrm{mL}\) of \(0.1\; \mathrm{M} \mathrm{HCl}\) and the solution made up to \(500\; \mathrm{mL}\) To \(20 \;\mathrm{mL}\) of this solution \(\frac{1}{2}\; \mathrm{mL}\) of \(5\; \mathrm{M\;NaOH}\) is added. The \(\mathrm{pH}\) of the solution is [Given : \(\mathrm{pK}_{\mathrm{a}}\) of acetic acid \(=4.75,\) molar mass of acetic acid \(=60 \mathrm{g} / \mathrm{mol}, \log 3=0.4771]\) Neglect any changes in volume

  1. A \(7.2\)
  2. B \(6.43\)
  3. C \(3.22\)
  4. D \(5.23\)
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Answer & Solution

Correct Answer

(D) \(5.23\)

Step-by-step Solution

Detailed explanation

Sol. 3 gm Acetic Acid \(+250 \mathrm{ml}\; 0.1 \mathrm{M} \;\mathrm{HCl}+\) Water \(\longrightarrow\) made to 500 ml solution. \(\Rightarrow 500 \mathrm{ml}\) solution has \(25 \mathrm{meq}\) of \(\mathrm{HCl}\) \(50 \mathrm{meq}\) of \(\mathrm{CH}_{3} \mathrm{COOH}\)…
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