JEE Mains · Chemistry · STD 11 - 6.2. Equilibrium - II (icon Equilibrium)
Arrange the following solutions is the decreasing order of \(pOH\) \((A)\) \(0.01 \,M\, HCl\) \((B)\) \(0.01 \,M \,NaOH\) \((C)\) \(0.01 \,M \,CH _{3} COONa\) \((D)\) \(0.01 \,M \,NaCl\)
- A \((B)>(C)>(D)>(A)\)
- B \(( A )>( C )>( D )>( B )\)
- C \((B)>(D)>(C)>(A)\)
- D \(( A )>( D )>( C )>( B )\)
Answer & Solution
Correct Answer
(D) \(( A )>( D )>( C )>( B )\)
Step-by-step Solution
Detailed explanation
\((i)\) \(10^{-2} M HCl \Rightarrow\left[ H ^{+}\right]=10^{-2} M \rightarrow pH =2\) \((ii)\) \(10^{-2} M NaOH \Rightarrow\left[ OH ^{-}\right]=10^{-2} M \rightarrow PoH =2\) \((iii)\)…
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