JEE Mains · Physics · STD 11- 8. mechanical properties of solids
Steel ruptures when a shear of \(3 .5 \times 10^8\,\,N\,m^{-2}\) is applied. The force needed to punch a \(1\,cm\) diameter hole in a steel sheet \(0.3\,cm\) thick is nearly
- A \(1.4\,\times 10^4\,N\)
- B \(2.7\,\times 10^4\,N\)
- C \(3.3\,\times 10^4\,N\)
- D \(1.1\,\times 10^4\,N\)
Answer & Solution
Correct Answer
(C) \(3.3\,\times 10^4\,N\)
Step-by-step Solution
Detailed explanation
Shearing strain is created along the side surface of the punched disk. Note that the forces exerted on the disk are exerted along the circum ference of the disk, and the total force exerted on its center only. Letus assume that the shearing stress along the side surface of the…
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