JEE Mains · Chemistry · STD 11 - 2. structure of atom
The difference between the radii of \(3^{\text {rd }}\) and \(4^{\text {th }}\) orbits of \(Li ^{2+}\) is \(\Delta R _{1}\). The difference between the radii of \(3^{\text {rd }}\) and \(4^{\text {th }}\) orbits of \(He ^{+}\) is \(\Delta R _{2}\). Ratio \(\Delta R _{1}: \Delta R _{2}\) is :
- A \(8:3\)
- B \(3:2\)
- C \(3:8\)
- D \(2:3\)
Answer & Solution
Correct Answer
(D) \(2:3\)
Step-by-step Solution
Detailed explanation
\(\frac{\Delta R _{1}}{\Delta R _{2}}=\frac{\left( r _{4}- r _{3}\right)_{4^{2+}}}{\left( r _{4}- r _{3}\right)_{ He ^{+}}}=\frac{\frac{4^{2}}{3}-\frac{3^{2}}{3}}{\frac{4^{2}}{2}-\frac{3^{2}}{2}}=\frac{7 / 3}{7 / 2}=\frac{2}{3}\)
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