JEE Mains · Chemistry · STD 11 - 9. Hydricarbon
\(17\,mg\) of a hydrocarbon (M.F. \(C _{10} H _{16}\) ) takes up \(8.40\,mL\) of the \(H _2\) gas measured at \(0^{\circ}\,C\) and \(760\,mm\) of \(Hg\). Ozonolysis of the same hydrocarbon yields \(Image\) The number of double bond/s present in the hydrocarbon is \(...........\).
- A \(3\)
- B \(6\)
- C \(9\)
- D \(12\)
Answer & Solution
Correct Answer
(A) \(3\)
Step-by-step Solution
Detailed explanation
Moles of hydrocarbon \(=\frac{17 \times 10^{-3}}{136}=1.25 \times 10^{-4}\) Mole of \(H _2\) gas \(\Rightarrow 1 \times \frac{8.40}{1000}= n \times 0.0821 \times 273\) \(\Rightarrow n =3.75 \times 10^{-4}\) Hydrogen molecule used for 1 molecule of hydrocarbon is 3…
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