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JEE Mains · Physics · STD 11 - Waves and sound
  • JEE Mains 2020
  • Medium
  • Numerical

A uniform thin rope of length \(12\, m\) and mass \(6\, kg\) hangs vertically from a rigid support and a block of mass \(2\, kg\) is attached to its free end. A transverse short wavetrain of wavelength \(6\, cm\) is produced at the lower end of the rope. What is the wavelength of the wavetrain (in \(cm\) ) when it reaches the top of the rope \(?\)

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Answer & Solution

Correct Answer

(B) \(12\)

Step-by-step Solution

Detailed explanation

\(V \propto \lambda \quad T _{2}=8 g\)

\(T _{1}=2 g\)

\(\frac{ V _{1}}{ V _{2}}=\frac{\lambda_{1}}{\lambda_{2}}\)

\(\lambda_{2}=\frac{ V _{2}}{ V _{1}} \lambda_{1}=\sqrt{\frac{ T _{2}}{ T _{1}}} \times \lambda_{1}\)

\(=\sqrt{\frac{8 g }{2 g }} \lambda_{1}=2 \times 6=12 cm\)

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