JEE Mains · Chemistry · STD 11 - 9. Hydricarbon
The final product \(\mathrm{A}\), formed in the following reaction sequence is: \(\mathrm{Ph}-\mathrm{CH}=\mathrm{CH}_2 \xrightarrow[\text { (iii) } \mathrm{HBr}{(iv) \mathrm{Mg}, ether, then \mathrm{HCHO} / \mathrm{H}_3 \mathrm{O}^{+}}]{{(i)BH_3}{\text { (ii) } \mathrm{H}_2 \mathrm{O}_2,{ }^{\text {(-) }} \mathrm{OH}}} \mathrm{A}\)
- A \(\mathrm{Ph}-\mathrm{CH}_2-\mathrm{CH}_2-\mathrm{CH}_3\)
- D \(\mathrm{Ph}-\mathrm{CH}_2-\mathrm{CH}_2-\mathrm{CH}_2-\mathrm{OH}\)
Answer & Solution
Correct Answer
(D) \(\mathrm{Ph}-\mathrm{CH}_2-\mathrm{CH}_2-\mathrm{CH}_2-\mathrm{OH}\)
Step-by-step Solution
Detailed explanation
\(\mathrm{PhCH}=\mathrm{CH}_2 \xrightarrow{\mathrm{B}_2 \mathrm{H}_6 / \mathrm{H}_2 \mathrm{O}_2, \mathrm{OH}^{-}} \mathrm{PhCH}_2 \mathrm{CH}_2 \mathrm{OH}\)…
See the Complete Solution
Get step-by-step explanations for this and 2.5 Lakh+ more JEE, NEET & CET questions.
- Unlock all solutions
- Practice the full chapter
- Track accuracy across PYQs
4.8 rated on Google Play · 14,000+ reviews
More questions from Chemistry
- In the above chemical reaction sequence " \(\mathrm{A}\) " and " \(\mathrm{B}\) " respectively are :
JEE Mains 2024 Medium - Quantitative analysis of an organic compound (X) shows following % composition.
C : \(14.5 \%\)
Cl : 64.46%
H: 1.8 %
(Empirical formula mass of the compound \((\mathrm{X})\) is __________ \(\times 10^{-1}\)
(Given molar mass in \(\mathrm{g} \mathrm{mol}^{-1}\) of \(\mathrm{C}: 12, \mathrm{H}: 1, \mathrm{O}: 16, \mathrm{Cl}: 35.5\))JEE Mains 2025 Medium - The isomer(s) of \(\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{4} \mathrm{Cl}_{2}\right]\) that has/have a \(\mathrm{Cl}-\mathrm{Co}-\mathrm{Cl}\) angle of \(90^{\circ},\) is/areJEE Mains 2020 Hard
- The standard entropy change for the reaction \(4 Fe ( s )+3 O _{2}( g ) \rightarrow 2 Fe _{2} O _{3}( s )\) is \(-550\, JK ^{-1}\) at \(298 \,K\). [Given : The standard enthalpy change for the reaction is \(-165\, kJ\, mol ^{-1}\). The temperature in \(K\) at which the reaction attains equilibrium is ... . (Nearest Integer)JEE Mains 2022 Medium
- \(3 \;g\) of acetic acid is added to \(250\; \mathrm{mL}\) of \(0.1\; \mathrm{M} \mathrm{HCl}\) and the solution made up to \(500\; \mathrm{mL}\) To \(20 \;\mathrm{mL}\) of this solution \(\frac{1}{2}\; \mathrm{mL}\) of \(5\; \mathrm{M\;NaOH}\) is added. The \(\mathrm{pH}\) of the solution is [Given : \(\mathrm{pK}_{\mathrm{a}}\) of acetic acid \(=4.75,\) molar mass of acetic acid \(=60 \mathrm{g} / \mathrm{mol}, \log 3=0.4771]\) Neglect any changes in volumeJEE Mains 2020 Hard
- Consider the following gaseous equilibrium in a closed container of volume "V" at T(K):
\(P_{2}(g)+Q_{2}(g)\rightleftharpoons2PQ(g)\).
2 moles each of \(P_{2}(g)\), \(Q_{2}(g)\) and PQ (g) are present at equilibrium. Now one mole each of '\(P_{2}\)' and '\(Q_{2}\)' are added to the equilibrium keeping the temperature at T(K). The number of moles of \(P_{2}\), \(Q_{2}\) and PQ at the new equilibrium, respectively, are -JEE Mains 2026 Medium
More PYQs from JEE Mains
- When the position vector \(\overrightarrow{ r }=x \hat{ i }+y \hat{ j }+z \hat{ k }\) changes sign as \(-\overrightarrow{ r }\), which one of the following vector will not flip under sign change ?JEE Mains 2026 Easy
- Shown in the figure is rigid and uniform one meter long rod \(AB\) held in horizontal position by two strings tied to its ends and attached to the ceiling. The rod is of mass \('m'\) and has another weight of mass \(2m\) hung at a distance of \(75\, cm\) from \(A\). The tension in the string at \(A\) is\(....mg\)
JEE Mains 2020 Hard - Let the values of p , for which the shortest distance between the lines \(\frac{x+1}{3}=\frac{y}{4}=\frac{z}{5}\) and \(\overrightarrow{\mathrm{r}}=(\mathrm{p} \hat{\mathrm{i}}+2 \hat{\mathrm{j}}+\hat{\mathrm{k}})+\lambda(2 \hat{\mathrm{i}}+3 \hat{\mathrm{j}}+4 \hat{\mathrm{k}})\) is \(\frac{1}{\sqrt{6}}\), be \(\mathrm{a}, \mathrm{b}\), \((a \lt b)\). Then the length of the latus rectum of the ellipse \(\frac{x^2}{a^2}+\frac{y^2}{b^2}=1\) is :-JEE Mains 2025 Medium
- Let \(A=\left[\begin{array}{ccc}2 & 1 & 0 \\ 1 & 2 & -1 \\ 0 & -1 & 2\end{array}\right]\). If \(|\operatorname{adj}(\operatorname{adj}(\operatorname{adj} 2 A))|=(16)^{ n }\), then \(n\) is equal toJEE Mains 2023 Hard
- If the lines \(\frac{x-1}{2}=\frac{2-y}{-3}=\frac{z-3}{\alpha}\) and \(\frac{x-4}{5}=\frac{y-1}{2}=\frac{z}{\beta}\) intersect, then the magnitude of the minimum value of \(8 \alpha \beta\) is \(...............\).JEE Mains 2023 Hard
-
In the first configuration (1) as shown in the figure, four identical charges \(\left(q_0\right)\) are kept at the corners \(A, B, C\) and \(D\) of square of side length 'a'. In the second configuration (2), the same charges are shifted to mid points \(\mathrm{G}, \mathrm{E}, \mathrm{H}\) and F, of the square, If \(\mathrm{K}=\frac{1}{4 \pi \varepsilon_0}\), the difference between the potential energies of configuration (2) and (1) is given by :JEE Mains 2025 Hard