JEE Mains · Chemistry · STD 12 -1. Solution and colligative properties
\(1.46 \,\mathrm{~g}\) of a biopolymer dissolved in a \(100\, \mathrm{~mL}\) water at \(300\, \mathrm{~K}\) exerted an osmotic pressure of \(2.42 \times 10^{-3}\) \(bar.\) The molar mass of the biopolymer is \(.....\,\times 10^{4} \,\mathrm{~g}\,\mathrm{~mol}^{-1}\). (Round off to the Nearest Integer) [Use : \(\mathrm{R}=0.083\, \mathrm{~L}\, bar \,\mathrm{mol}^{-1} \,\mathrm{~K}^{-1}\) ]
- A \(7\)
- B \(5\)
- C \(91\)
- D \(15\)
Answer & Solution
Correct Answer
(D) \(15\)
Step-by-step Solution
Detailed explanation
\(\pi=\mathrm{CRT}\) \(; \pi=\) osmotic pressure \(\mathrm{C}=\) molarity \(T=\) Temperature of solution let the molar mass be \(\mathrm{M}\, \mathrm{gm} / \mathrm{mol}\)…
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