JEE Mains · Chemistry · STD 12 -1. Solution and colligative properties
\(1\, \mathrm{~kg}\) of \(0.75\) molal aqueous solution of sucrose can be cooled up to \(-4^{\circ} \mathrm{C}\) before freezing. The amount of ice (in \(g\)) that will be separated out is .... . (Nearest integer) \(\left[\right.\) Given \(\left.: \mathrm{K}_{\mathrm{f}}\left(\mathrm{H}_{2} \mathrm{O}\right)=1.86\, \mathrm{~K}\, \mathrm{~kg}\, \mathrm{~mol}^{-1}\right]\)
- A \(342\)
- B \(841\)
- C \(518\)
- D \(277\)
Answer & Solution
Correct Answer
(C) \(518\)
Step-by-step Solution
Detailed explanation
Let mass of water initially present \(=\mathrm{x\,gm}\) \(\Rightarrow \text { Mass of sucrose }=(1000-\mathrm{x})\, \mathrm{gm}\) \(\Rightarrow \text { moles of sucrose }=\left(\frac{1000-\mathrm{x}}{342}\right)\)…
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