JEE Mains · Chemistry · STD 11 - 1. Some basic concept of chemistry
The volume of \(HCl\), containing \(73\,g\,L ^{-1}\), required to completely neutralise \(NaOH\) obtained by reacting \(0.69\,g\) of metallic sodium with water, is \(........mL\). (Nearest Integer) (Given : molar Masses of \(Na , Cl , O , H\) are \(23\), \(35.5,16\) and \(1\,g\,mol ^{-1}\) respectively)
- A \(14\)
- B \(12\)
- C \(15\)
- D \(13\)
Answer & Solution
Correct Answer
(C) \(15\)
Step-by-step Solution
Detailed explanation
Mole of \(Na =\frac{0.69}{23}=3 \times 10^{-2}\) \(Na + H _2 O \longrightarrow NaOH +\frac{1}{2} H _2\) By using \(POAC\) Moles of \(NaOH =3 \times 10^{-2}\) \(NaOH\) reacts with \(HCl\) No. of equivalent of \(NaOH = No\). of equivalent of \(HCl\)…
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