JEE Advanced · Chemistry · 11. s Block
\(\mathrm{MgSO}_4\) on reaction with \(\mathrm{NH}_4 \mathrm{OH}\) and \(\mathrm{Na}_2 \mathrm{HPO}_4\) forms a white crystalline precipitate. What is its formula?
- A \(\mathrm{Mg}\left(\mathrm{NH}_4\right) \mathrm{PO}_4\)
- B \(\mathrm{Mg}_3\left(\mathrm{PO}_4\right)_2\)
- C \(\mathrm{MgCl}_2 \cdot \mathrm{MgSO}_4\)
- D \(\mathrm{MgSO}_4\)
Answer & Solution
Correct Answer
(A) \(\mathrm{Mg}\left(\mathrm{NH}_4\right) \mathrm{PO}_4\)
Step-by-step Solution
Detailed explanation
\(\mathrm{MgSO}_4\) on reaction with \(\mathrm{Na}_2 \mathrm{HPO}_4\) (disodium hydrogen phosphate) in presence of \(\mathrm{NH}_4 \mathrm{OH}\) to give white precipitate of magnesium ammonium phosphate \(\left(\mathrm{Mg}\left(\mathrm{NH}_4\right) \mathrm{PO}_4\right)\).
\(\text{MgSO} _4+ \text{Na} _2 \text{HPO} _4+ \text{NH} _4 \text{OH} \longrightarrow\) \(\underset{\text {White ppt}}{\text{Mg} \left(\text{NH} _4\right) \text{PO} _4} \downarrow+ \text{Na} _2 \text{SO} _4+ \text H _2\text O\)
\(\text{MgSO} _4+ \text{Na} _2 \text{HPO} _4+ \text{NH} _4 \text{OH} \longrightarrow\) \(\underset{\text {White ppt}}{\text{Mg} \left(\text{NH} _4\right) \text{PO} _4} \downarrow+ \text{Na} _2 \text{SO} _4+ \text H _2\text O\)
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