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JEE Advanced · Physics · 4. Motion in 2D

A particle of mass m is moving in the xy-plane such that its velocity at a point (x, y) is given as v=αyx+2xy where α is a non-zero constant. What is the force F acting on the particle?

  1. A F=2mα2xx+yy
  2. B F=mα2yx+2xy
  3. C F=2mα2yx+xy
  4. D F=mα2xx+2yy
Verified Solution

Answer & Solution

Correct Answer

(A) F=2mα2xx+yy

Step-by-step Solution

Detailed explanation

As force is given by, F=mdvdt. Given: v=αyx+2xy, where velocity along x-axis is vx=αy and velocity along y-axis is vy=2xα.
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