ExamBro
ExamBro
JEE Advanced · Chemistry · 6. Thermodynamics (C)

Match the thermodynamic processes given under Column I with the expressions given under Column II.
  Column I   Column II
A. Freezing of water at 273 K and 1 atm P. q=0
B. Expansion of 1 mol of an ideal gas into a vacuum under isolated conditions Q. w=0
C. Mixing of equal volumes of two ideal gases at constant temperature and pressure in an isolated container R. ΔSsys<0
D. Reversible heating of H2(g) at 1 atm from 300 K to 600 K, followed by reversible cooling to 300 K at 1 atm S. ΔU=0
    T. ΔG=0

  1. A a-r;b-s,t;c-r,s,t;d-s,t;
  2. B a-q,r;b-q;c-q;d-s,t;
  3. C a-r,t;b-p,q,s;c-p,q,s;d-p,q,s,t;
  4. D a-q,r,s;b-s,t;c-q,r,s;d-t;
Verified Solution

Answer & Solution

Correct Answer

(C) a-r,t;b-p,q,s;c-p,q,s;d-p,q,s,t;

Step-by-step Solution

Detailed explanation

A - H2O(l)H2O(s) at 273 K. & 1 atm
H=-ve=q
Ssys<0, G=0
w0 (as water expands on freezing), U0
B - Free expansion of ideal gas.
q = 0
w = 0
U=0
Ssys>0
G<0
C - Mixing of equal volume of ideal gases at constant pressure & temp in an isolated container
q = 0, w = 0, U=0 , Ssys>0 , G<0
Image
q = 0, w = 0, U=0 , G=0 , Ssys=0
Same subject
Explore more questions on app
From JEE Advanced
Explore more questions on app